# finding multiples of a number in Python

## Issue

I’m trying to write a code that lets me find the first few multiples of a number. This is one of my attempts:

``````def printMultiples(n, m):
for m in (n,m):
print(n, end = ' ')
``````

I figured out that, by putting `for m in (n, m):`, it would run through the loop for whatever number was `m`.

``````def printMultiples(n, m):
'takes n and m as integers and finds all first m multiples of n'
for m in (n,m):
if n % 2 == 0:
while n < 0:
print(n)
``````

After multiple searches, I was only able to find a sample code in java, so I tried to translate that into python, but I didn’t get any results. I have a feeling I should be using the `range()` function somewhere in this, but I have no idea where.

## Solution

If you’re trying to find the first `count` multiples of `m`, something like this would work:

``````def multiples(m, count):
for i in range(count):
print(i*m)
``````

Alternatively, you could do this with range:

``````def multiples(m, count):
for i in range(0,count*m,m):
print(i)
``````

Note that both of these start the multiples at `0` – if you wanted to instead start at `m`, you’d need to offset it by that much:

``````range(m,(count+1)*m,m)
``````