# How to find corner (x, y) coordinate points on image Python OpenCV?

## Issue

This is a truck container image but from the top view. First, I need to find the rectangle and know each corner position. The goal is to know the dimension of the container.

## Solution

Here’s a simple approach:

1. Obtain binary image. Load image, convert to grayscale,
Gaussian blur, then Otsu’s threshold.

2. Find distorted bounding rectangle contour and corners. We find contours then filter using contour area to isolate the rectangular contour. Next we find the distorted bounding rectangle with `cv2.minAreaRect()` and the corners with `cv2.boxPoints()`

Detected bounding rectangle `->` Mask `->` Detected corners

Corner points

``````(188, 351)
(47, 348)
(194, 32)
(53, 29)
``````

Code

``````import cv2
import numpy as np

# Load image, grayscale, blur, Otsu's threshold
gray = cv2.cvtColor(image, cv2.COLOR_BGR2GRAY)
blur = cv2.GaussianBlur(gray, (5,5), 0)
thresh = cv2.threshold(blur, 0, 255, cv2.THRESH_BINARY + cv2.THRESH_OTSU)[1]

# Find distorted bounding rect
cnts = cv2.findContours(thresh, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_SIMPLE)
cnts = cnts[0] if len(cnts) == 2 else cnts[1]
for c in cnts:
area = cv2.contourArea(c)
if area > 5000:
# Find distorted bounding rect
rect = cv2.minAreaRect(c)
corners = cv2.boxPoints(rect)
corners = np.int0(corners)

# Draw corner points
corners = corners.tolist()
print(corners)
for corner in corners:
x, y = corner
cv2.circle(image, (x, y), 5, (36,255,12), -1)

cv2.imshow('thresh', thresh)
cv2.imshow('image', image)