Issue
I have this query to get the count values in range dates (with a unique date filter to one day to view selection detail):
SELECT `dates`.`date`, COUNT(*)
FROM (
SELECT CURDATE() - INTERVAL (units.mul + (10 * tens.mul) + (100 * hundreds.mul) + (200 * thousands.mul)) DAY AS `date`
FROM (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS units
CROSS JOIN (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS tens
CROSS JOIN (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS hundreds
CROSS JOIN (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS thousands
) `dates`
LEFT JOIN `prices` ON (`prices`.`date` = `dates`.`date`)
WHERE `dates`.`date` = '2020-07-07'
GROUP BY `dates`.`date`
ORDER BY `dates`.`date` ASC;
+------------+-----------+
| date | COUNT(*) |
+------------+-----------+
| 2020-07-07 | 150840 |
+------------+-----------+
1 row in set (0.06 sec)
But same query only on prices table the result is:
SELECT COUNT(*) FROM `prices` WHERE `date` = '2020-07-07';
+----------+
| COUNT(*) |
+----------+
| 37710 |
+----------+
1 row in set (0.01 sec)
Why first query result is not:
+------------+----------+
| date | COUNT(*) |
+------------+----------+
| 2020-07-07 | 37710 |
+------------+----------+
1 row in set (0.06 sec)
Thanks!
Solution
37710 * 4 = 150840 check your query without the join and you have 4 rows with 2020-07-07 I suspect typo 200 * thousands.mul should be 1000 * thousands.mul
SELECT `dates`.`date`, COUNT(*)
FROM (
SELECT CURDATE() - INTERVAL (units.mul + (10 * tens.mul) + (100 * hundreds.mul) + (200 * thousands.mul)) DAY AS `date`
FROM (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS units
CROSS JOIN (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS tens
CROSS JOIN (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS hundreds
CROSS JOIN (SELECT 0 AS mul UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) AS thousands
) `dates`
#LEFT JOIN `prices` ON (`prices`.`date` = `dates`.`date`)
WHERE `dates`.`date` = '2020-07-07'
GROUP BY `dates`.`date`
ORDER BY `dates`.`date` ASC;
+------------+----------+
| date | COUNT(*) |
+------------+----------+
| 2020-07-07 | 4 |
+------------+----------+
1 row in set (0.011 sec)
Answered By – P.Salmon
Answer Checked By – Cary Denson (AngularFixing Admin)